0=4r^2-52+169

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Solution for 0=4r^2-52+169 equation: 



0=4r^2-52+169

We move all terms to the left:

0-(4r^2-52+169)=0

We add all the numbers together, and all the variables

-(4r^2-52+169)=0

We get rid of parentheses

-4r^2+52-169=0

We add all the numbers together, and all the variables

-4r^2-117=0

a = -4; b = 0; c = -117;
Δ = b2-4ac
Δ = 02-4·(-4)·(-117)
Δ = -1872
Delta is less than zero, so there is no solution for the equation

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